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MISCELLANEOUS EXERCISE-8 · Q71

Q.Find f(a)f(a), if ff is continuous at x=ax=a where, f(x)=1−cos⁡[7(x−π)]5(x−π)2f(x) = \dfrac{1-\cos[7(x-\pi)]}{5(x-\pi)^2}, for x≠πx \ne \pi at a=πa = \pi.

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f(x)=1−cos⁡[7(x−π)]5(x−π)2f(x)=\dfrac{1-\cos[7(x-\pi)]}{5(x-\pi)^2} for x≠πx\ne\pi, continuous at π\pi, so f(π)=lim⁡x→πf(x)f(\pi)=\displaystyle\lim_{x\to\pi} f(x). …

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