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MISCELLANEOUS EXERCISE-8 · Q61

Q.Identify discontinuities if any for the following function as either a jump or a removable discontinuity on its domain: f(x)=x2+x−3f(x) = x^2+x-3, for x∈[−5,−2)x \in [-5,-2), =x2−5= x^2-5, for x∈(−2,5]x \in (-2,5].

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f(x)=x2+x−3f(x)=x^2+x-3 for x∈[−5,−2)x\in[-5,-2), and f(x)=x2−5f(x)=x^2-5 for x∈(−2,5]x\in(-2,5]; note x=−2x=-2 belongs to neither piece, so f(−2)f(-2) is not defined at all.

Left-hand limit: lim⁡x→−2−(x2+x−3)=4−2−3=−1\displaystyle\lim_{x\to-2^-}(x^2+x-3)=4-2-3=-1.

Right-hand limit: lim⁡x→−2+(x2−5)=4−5=−1\displaystyle\lim_{x\to-2^+}(x^2-5)=4-5=-1. …

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