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MISCELLANEOUS EXERCISE-8 · Q69

Q.Find aa and bb if the following function is continuous on the interval indicated against it: f(x)=ax2+bx+1f(x) = ax^2+bx+1, for ∣2x−3∣≥2|2x-3| \ge 2, =3x+2= 3x+2, for 12<x<52\dfrac12 < x < \dfrac52.

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f(x)=ax2+bx+1f(x)=ax^2+bx+1 for ∣2x−3∣≥2|2x-3|\ge2 (i.e. x≥52x\ge\tfrac52 or x≤12x\le\tfrac12), and f(x)=3x+2f(x)=3x+2 for 12<x<52\tfrac12<x<\tfrac52; junctions at x=12x=\tfrac12 and x=52x=\tfrac52.

At x=12x=\tfrac12: f(12)=a4+b2+1f\left(\tfrac12\right)=\tfrac a4+\tfrac b2+1 (first piece). Right-hand limit: 3(12)+2=723\left(\tfrac12\right)+2=\tfrac72. Continuity: a4+b2+1=72\tfrac a4+\tfrac b2+1=\tfrac72; multiplying by 44: a+2b+4=14⇒a+2b=10.(i)a+2b+4=14\Rightarrow a+2b=10.\quad(i) …

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