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MISCELLANEOUS EXERCISE-8 · Q60

Q.Discuss the continuity of the following function at the point(s) or on the interval indicated against it: f(x)=2x2+x+1f(x) = 2x^2+x+1, for ∣x−3∣≥2|x-3| \ge 2, =x2+3= x^2+3, for 1<x<51 < x < 5.

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f(x)=2x2+x+1f(x)=2x^2+x+1 for ∣x−3∣≥2|x-3|\ge2 (i.e. x≤1x\le1 or x≥5x\ge5), and f(x)=x2+3f(x)=x^2+3 for 1<x<51<x<5; together these cover R\mathbb{R}, with junctions at x=1x=1 and x=5x=5.

At x=1x=1: f(1)=2+1+1=4f(1)=2+1+1=4 (first piece, since x=1x=1 satisfies x≤1x\le1). Right-hand limit: lim⁡x→1+(x2+3)=1+3=4\displaystyle\lim_{x\to1^+}(x^2+3)=1+3=4. These match, so ff is continuous at x=1x=1. …

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