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EXERCISE 8.1 · Q14

Q.Identify discontinuities for the following function as either a jump or a removable discontinuity: f(x)=x2−10x+21x−7f(x) = \dfrac{x^2-10x+21}{x-7}.

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f(x)=x2−10x+21x−7f(x)=\dfrac{x^2-10x+21}{x-7} is a rational function, continuous everywhere except where the denominator vanishes, i.e. except at x=7x=7; so f(7)f(7) is not defined.

Factorising, x2−10x+21=(x−3)(x−7)x^2-10x+21=(x-3)(x-7), so for x≠7x\ne7, f(x)=(x−3)(x−7)x−7=x−3f(x)=\dfrac{(x-3)(x-7)}{x-7}=x-3.

lim⁡x→7f(x)=lim⁡x→7(x−3)=4.\lim_{x\to7} f(x)=\lim_{x\to7}(x-3)=4. …

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