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EXERCISE 4.3 · Q35

Q.In the following expansion, find the indicated term: (x2−4x3)11\left(x^2-\dfrac{4}{x^3}\right)^{11}, 5th term.

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✓ Free question

Here a=x2,b=−4x3,n=11a=x^2,b=-\dfrac{4}{x^3},n=11. For t5t_5, r=4r=4. t5=11C4(x2)7(−4x3)4=330 x14⋅256x12=330(256)x2=84480x2t_5={}^{11}C_4(x^2)^7\left(-\dfrac{4}{x^3}\right)^4=330\,x^{14}\cdot\dfrac{256}{x^{12}}=330(256)x^2=84480x^2.

✓Final answer

The 5th term is 84480x284480x^2.

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