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EXERCISE 4.3 · Q40

Q.In the following expansion, find the indicated coefficient: coefficient of x8x^8 in (2x5−5x3)8\left(2x^5-\dfrac{5}{x^3}\right)^8.

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tr+1=8Cr(2x5)8−r(−5x3)r=8Cr28−r(−5)rx40−8rt_{r+1}={}^8C_r(2x^5)^{8-r}\left(-\dfrac5{x^3}\right)^r={}^8C_r2^{8-r}(-5)^rx^{40-8r}. Setting 40−8r=840-8r=8 gives r=4r=4. Coefficient $={}^8C_4(2)^4(-5)^4=70\ti …

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