Skip to content
EXERCISE 4.3 · Q56

Q.The coefficient of x2x^2 in the expansion of (1+2x)m(1+2x)^m is 112112. Find mm.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
43% · 56/129 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Coefficient of x2x^2 in (1+2x)m(1+2x)^m is mC2(2)2=4⋅m(m−1)2=2m(m−1)^mC_2(2)^2=4\cdot\dfrac{m(m-1)}2=2m(m-1). Given 2m(m−1)=1122m(m-1)=112, so m(m−1)=56m(m-1)=56, i.e. m2−m−56=0m^2-m-56=0, factoring (m−8)(m+7)=0(m-8)(m+7)=0, so m=8m=8 or m=−7m=-7 …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.