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EXERCISE 4.3 · Q39

Q.In the following expansion, find the indicated coefficient: coefficient of x3x^3 in (x2+32x)9\left(x^2+\dfrac{3\sqrt{2}}{x}\right)^9.

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tr+1=9Cr(x2)9−r(32x)r=9Cr(32)rx18−3rt_{r+1}={}^9C_r(x^2)^{9-r}\left(\dfrac{3\sqrt2}{x}\right)^r={}^9C_r(3\sqrt2)^rx^{18-3r}. Setting 18−3r=318-3r=3 gives r=5r=5. Coefficient $={}^9C_5(3\sqrt2)^5=126\times3^5\times(\sqrt2)^5=126\times243\times4\sqrt2=122 …

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