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EXERCISE 4.3 · Q43

Q.In the following expansion, find the indicated coefficient: coefficient of x−20x^{-20} in (x3−12x2)15\left(x^3-\dfrac{1}{2x^2}\right)^{15}.

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tr+1=15Cr(x3)15−r(−12x2)r=15Cr(−12)rx45−5rt_{r+1}={}^{15}C_r(x^3)^{15-r}\left(-\dfrac1{2x^2}\right)^r={}^{15}C_r\left(-\dfrac12\right)^rx^{45-5r}. Setting 45−5r=−2045-5r=-20 gives r=13r=13. Coefficient =15C13(−12)13={}^{15}C_{13}\left(-\dfrac12\right)^{13}. Since 15C13=15C2=105^{15}C_{13}={}^{15}C_2=105 and (−12)13=−18192\left(-\dfrac12\right)^{13}=-\dfrac1{8192}: coeffici …

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