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EXERCISE 4.3 · Q48

Q.Find the constant term (term independent of x) in the expansion of (2x2−5x)9\left(2x^2-\dfrac{5}{x}\right)^9.

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tr+1=9Cr(2x2)9−r(−5x)r=9Cr29−r(−5)rx18−3rt_{r+1}={}^9C_r(2x^2)^{9-r}\left(-\dfrac5x\right)^r={}^9C_r2^{9-r}(-5)^rx^{18-3r}. Setting 18−3r=018-3r=0 gives r=6r=6. Constant $={}^9C_6(2)^3(-5)^6=84\tim …

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