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EXERCISE 4.3 · Q42

Q.In the following expansion, find the indicated coefficient: coefficient of x−3x^{-3} in (x−12x)5\left(x-\dfrac{1}{2x}\right)^5.

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tr+1=5Crx5−r(−12x)r=5Cr(−12)rx5−2rt_{r+1}={}^5C_rx^{5-r}\left(-\dfrac1{2x}\right)^r={}^5C_r\left(-\dfrac12\right)^rx^{5-2r}. Setting 5−2r=−35-2r=-3 gives r=4r=4. Coefficient $={}^5C_4\left(-\dfrac12\right)^4=5\times\df …

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