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EXERCISE 4.3 · Q44

Q.Find the constant term (term independent of x) in the expansion of (2x+13x2)9\left(2x+\dfrac{1}{3x^2}\right)^9.

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tr+1=9Cr(2x)9−r(13x2)r=9Cr29−r(13)rx9−3rt_{r+1}={}^9C_r(2x)^{9-r}\left(\dfrac1{3x^2}\right)^r={}^9C_r2^{9-r}\left(\dfrac13\right)^rx^{9-3r}. Setting 9−3r=09-3r=0 gives r=3r=3. Constant $={}^9C_3(2)^6\left(\dfrac13\right)^3=84\times64\times\dfrac1 …

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