In the expansion of (a+b)n, the individual terms are labelled t1,t2,…,tn+1 in order, and the single formula that produces any one of them directly is the general term tr+1=nCran−rbr,0≤r≤n. The subscript convention takes a moment to internalise: the term numbered r+1 (not r) corresponds to choosing r copies of b, so to find, say, the 5th term one substitutes r=4, not r=5. This one formula answers three different kinds of exam question without ever writing out the full expansion. First, 'find the kth term' — substitute r=k−1 directly. Second, 'find the coefficient of xp' (or of a specific power in a mixed expression) — write the general term's power of the variable as an expression in r, set it equal to p, solve for r, and substitute back to get the coefficient. Third, 'find the term independent of x' (the constant term) — the same idea, but the target power is 0. All three question types appear together …