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EXERCISE 4.3 · Q37

Q.In the following expansion, find the indicated term: (13+a2)12\left(\dfrac{1}{3}+a^2\right)^{12}, 9th term.

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Here the binomial base is 13\dfrac13, the other term is a2a^2, n=12n=12. For t9t_9, r=8r=8. $t_9={}^{12}C_8\left(\dfrac13\right)^4(a^2)^8=495\cdot\dfrac1{81}\cdot a^{16}=\dfrac{495}{81} …

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