Q.Give IUPAC names to the following monosaccharides.
- CHO−CHOH−CH2OH
- CHO−(CHOH)3−CH2OH
- CH2OH−CO−(CHOH)3−CH2OH
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🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — Carbohydrates
Carbohydrates are organic compounds built from carbon, hydrogen and oxygen in a ratio close to (CH2O)n, which is why they are also called saccharides. Based on the number of sugar units they contain, they are classified as monosaccharides (single sugar units such as glucose and fructose), oligosaccharides (2-10 linked sugar units, such as the disaccharide sucrose), and polysaccharides (more than 10 linked units, such as starch, glycogen and cellulose). Monosaccharides are further divided by their functional group into aldoses (e.g., glucose, an aldehyde sugar) and ketoses (e.g., fructose, a ketone sugar). Sugar units join through a condensation reaction that releases water and forms a glycosidic bond; the reverse hydrolysis reaction breaks that bond by adding water back, releasing the individual m …
- 2,3-Dihydroxypropanal · 2. 2,3,4,5-Tetrahydroxypentanal · 3. …
Name as polyhydroxy aldehydes/ketones:
- 1. glyceraldehyde = a C3 aldehyde with OH on C2, C3: 2,3-dihydroxypropanal.
- 2. an aldopentose (ribose skeleton): 2,3,4,5-tetrahydroxypentanal. …
- Longest chain including the carbonyl; -al for CHO (C1), -one with a locant for the keto grou …
- CBSE 2026Set ANNUAL1 markMCQQ.Chitin is a linear polymer of ________ joined together by beta-1,4 glycosidic linkages.(a) alpha-1,4-glucan malto hydrolase(b) beta-D-glucose units(c) D-glycuronic acid(d) N-acetyl-D-glucosamine units
›Reveal solutionSolution
Chitin is built from repeating N-acetyl-D-glucosamine monomers joined by beta-1,4 glycosidic linkages.
Chitin is a structural homopolysaccharide, chemically very similar in architecture to cellulose (which is a beta-1,4-linked chain of plain D-glucose units), but chitin's repeating monomer is instead N-acetyl-D-glucosamine — a glucose derivative in which the hydroxyl group at carbon-2 is replaced by an acetylated amino group (-NHCOCH3). This substitution allows chitin to form very strong hydrogen-bonded microfibrils, which is why it makes such a tough structural material (fungal cell walls, insect and crustacean exoskeletons). The other options are the monomers/hydrolytic components of different molecul …
- CBSE 2025Set ANNUAL1 markMCQQ.The β-D Glucose units in cellulose are linked together by:(a) 1→3 Linkage.(b) N-acetyl side chains.(c) β-(1, 4) glycosidic Linkage.(d) N-acetyl D-Glucosamine.
›Reveal solutionSolution
Cellulose is a homopolysaccharide of β-D-glucose units, and the glucose monomers are linked together specifically by β-(1→4) glycosidic bonds, giving it a straight, unbranched, highly hydrogen-bonded chain.
Cellulose is the chief structural polysaccharide of plant cell walls. It is built entirely of D-glucose units in the β-anomeric configuration, joined by glycosidic bonds between carbon-1 of one glucose unit and carbon-4 of the next — hence a β-(1→4) linkage.
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- CBSE 2024Set ANNUAL1 markMCQQ.The linkage present in Lactose is _____.(a) α, β -1, 2 - glycosidic linkage(b) α -1, 4 - glycosidic linkage(c) β -1, 4 - glycosidic linkage(d) α -1, 4 - glycosidic linkage
›Reveal solutionSolution
Lactose = galactose + glucose joined by a β-1,4-glycosidic bond.
Lactose is a disaccharide made of one unit of β-D-galactose and one unit of β-D-glucose. The two monosaccharides are joined through their C-1 (of galactose, β-configuration) and C-4 (of glucose) carbons, i.e. a β-1,4-g …
- CBSE 2023Set ANNUAL1 markMCQQ.The glycosidic linkage present in maltose is _______.(a) α,β-1,2-glycosidic linkage(b) α-1,4-glycosidic linkage(c) β-1,4-glycosidic linkage(d) α-1,6-glycosidic linkage
›Reveal solutionSolution
Maltose is two α-D-glucose units joined between C1 of one and C4 of the other.
Maltose is a disaccharide made of two α-D-glucopyranose units linked through an α-1,4-glycosidic bond — the anomeric (C1, α-configured) carbon of one glucose unit is joined via an oxygen bridge to the C …
- CBSE 2018Set ANNUAL1 markQ.On adding conc. H2SO4 to sugar a black mass is obtained. Identify the black mass.
›Reveal solutionSolution
Concentrated sulphuric acid removes the elements of water from sucrose, charring it to carbon.
Concentrated sulphuric acid is a powerful dehydrating agent. On sugar (sucrose, C12H22O11), it removes water (in the ratio corresponding to the empirical formula, effectively H2O units) from the sugar molecule, leaving behind a black, porous mass of elemental carbon and releasing heat and steam/gases …
- CBSE 2018Set ANNUAL1 markMCQQ.The number of primary and secondary hydroxyl groups in ribose are —(a) 1, 3(b) 2, 3(c) 3, 1(d) 3, 2
›Reveal solutionSolution
Ribose's open-chain form has OH on C2/C3/C4 (secondary) and C5 (primary).
The open-chain structure of ribose (an aldopentose) is CHO−CHOH−CHOH−CHOH−CH2OH (C1 to C5).
- C1 bears the aldehyde group (−CHO), no −OH here.
- C2, C3, C4 each bear a hydroxyl on a carbon attached to two other carbons — these are secondary hydroxyls (3 in total). …
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