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Question 79 of 83

Q.Identify 'A' and 'B' in the following reaction and rewrite the complete reaction: CH3−CH=CH2→PeroxideHBrA→−KBralcoholic KCNBCH_3-CH=CH_2 \xrightarrow[Peroxide]{HBr} A \xrightarrow[-KBr]{alcoholic\ KCN} B

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2025Subjective· 2mImportance★★★★★
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Peroxide-effect HBr addition to propene gives anti-Markovnikov A = 1-bromopropane; alc. KCN then gives B = butanenitrile.

CH3−CH=CH2→PeroxideHBrACH_3-CH=CH_2 \xrightarrow[Peroxide]{HBr} A: in the presence of peroxide, HBr adds across the double bond by the anti-Markovnikov (Kharasch/free-radical) mechanism, so Br ends up on the terminal (less substituted) carbon:

CH3−CH=CH2+HBr→peroxideCH3−CH2−CH2−BrCH_3-CH=CH_2 + HBr \xrightarrow{peroxide} CH_3-CH_2-CH_2-Br (A = 1-bromopropane)

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