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Exercise 6.6 · Q84

Q.In a certain culture of bacteria the rate of increase is proportional to the number present. If it is found that the number doubles in 4 hours, find the number of times the bacteria are increased in 12 hours.

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✓ Free question

Let xx be the number of bacteria at time tt: x=x0ektx=x_0e^{kt}. Doubling in 44 h means e4k=2e^{4k}=2. In 12=3×412=3\times4 h: xx0=e12k=(e4k)3=23=8\dfrac{x}{x_0}=e^{12k}=(e^{4k})^3=2^3=8. So the bacteria increase 88 times in 1212 hours.

✓Final answer

8 times8\text{ times}

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