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Exercise 6.1 · Q8

Q.Determine the order and degree of the differential equation: [1+(dydx)2]3/2=8d2ydx2\left[1+\left(\dfrac{dy}{dx}\right)^2\right]^{3/2}=8\dfrac{d^2y}{dx^2}

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The equation is [1+(dydx)2]3/2=8d2ydx2\left[1+\left(\dfrac{dy}{dx}\right)^2\right]^{3/2}=8\dfrac{d^2y}{dx^2}. Squaring both sides clears the 3/23/2 power: [1+(dydx)2]3=64(d2ydx2)2\left[1+\left(\dfrac{dy}{dx}\right)^2\right]^3=64\left(\dfrac{d^2y}{dx^2}\right)^2. The highest derivative is $\dfrac{ …

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