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Exercise 6.6 · Q87

Q.The rate of growth of bacteria is proportional to the number present. If initially there were 1000 bacteria and the number doubles in 1 hour, find the number of bacteria after 2122\dfrac12 hours. [Take 2=1.414\sqrt2=1.414]

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Let x=1000 ektx=1000\,e^{kt}. Doubling in 11 h: ek=2e^{k}=2. At t=2.5t=2.5: $x=1000,e^{2.5k}=1000\cdot2^{2.5}=1000\cdot4\sqrt2=1000\times4\time …

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