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Exercise 6.6 · Q85

Q.If the population of a country doubles in 60 years, in how many years will it be triple (treble) under the assumption that the rate of increase is proportional to the number of inhabitants? [Given log⁡2=0.6912, log⁡3=1.0986\log2=0.6912,\ \log3=1.0986]

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✓ Free question

Let P=P0ektP=P_0e^{kt}. Doubling in 6060 years: 2=e60k⇒k=log⁡2602=e^{60k}\Rightarrow k=\dfrac{\log2}{60}. Tripling takes time TT: 3=ekT⇒T=log⁡3k=60log⁡3log⁡2=60(1.0986)0.6912≈95.363=e^{kT}\Rightarrow T=\dfrac{\log3}{k}=\dfrac{60\log3}{\log2}=\dfrac{60(1.0986)}{0.6912}\approx95.36 years.

✓Final answer

T=60log⁡3log⁡2≈95.4 yearsT=\dfrac{60\log3}{\log2}\approx95.4\text{ years}

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