Skip to content
Exercise 6.1 · Q9

Q.Determine the order and degree of the differential equation: (d3ydx3)1/2−(dydx)1/3=20\left(\dfrac{d^3y}{dx^3}\right)^{1/2}-\left(\dfrac{dy}{dx}\right)^{1/3}=20

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
5% · 9/177 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

The equation is (d3ydx3)1/2−(dydx)1/3=20\left(\dfrac{d^3y}{dx^3}\right)^{1/2}-\left(\dfrac{dy}{dx}\right)^{1/3}=20. Isolating the highest-derivative term and squaring gives d3ydx3=[20+(dydx)1/3]2=400+40(dydx)1/3+(dydx)2/3\dfrac{d^3y}{dx^3}=\left[20+\left(\dfrac{dy}{dx}\right)^{1/3}\right]^2 =400+40\left(\dfrac{dy}{dx}\right)^{1/3}+\left(\dfrac{dy}{dx}\right)^{2/3}. The order is 33 (from d3ydx3\dfrac{d^3y}{dx^3}), but no further algebraic step removes the fractional powers 1/31/3 and 2/32/3 on $\dfr …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.