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Miscellaneous Exercise 6(II) · Q131

Q.Solve: log⁡dydx=2x+3y\log\dfrac{dy}{dx}=2x+3y

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log⁡dydx=2x+3y\log\dfrac{dy}{dx}=2x+3y is identical in form to Exercise 6.3 Q2(ii): dydx=e2xe3y\dfrac{dy}{dx}=e^{2x}e^{3y} separates as e−3ydy=e2xdxe^{-3y}dy=e^{2x}dx, integra …

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