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Example · Example 3

Q.Evaluate lim⁡x→2x2−4x−2\lim_{x\to2}\dfrac{x^2-4}{x-2}.

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✓ Free question

Direct substitution gives 00\dfrac{0}{0}, an indeterminate form (Section 2), so factor first:

x2−4x−2=(x−2)(x+2)x−2=x+2(x≠2).\frac{x^2-4}{x-2} = \frac{(x-2)(x+2)}{x-2} = x+2 \quad (x\neq2).

Since the limit never depends on the value at x=2x=2 itself (Section 1), lim⁡x→2(x+2)=4\lim_{x\to2}(x+2) = 4.

✓Final answer

lim⁡x→2x2−4x−2=4\lim_{x\to2}\dfrac{x^2-4}{x-2} = 4

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