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Exercise: Limits of Exponential and L... · Q22

Q.Evaluate lim⁡x→0ln⁡(1+3x)sin⁡2x\lim_{x\to0}\dfrac{\ln(1+3x)}{\sin2x}.

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ln⁡(1+3x)sin⁡2x=3⋅ln⁡(1+3x)3x2⋅sin⁡2x2x.\frac{\ln(1+3x)}{\sin2x} = \frac{3\cdot\dfrac{\ln(1+3x)}{3x}}{2\cdot\dfrac{\sin2x}{2x}}.

As x→0x\to0: ln⁡(1+3x)3x→1\dfrac{\ln(1+3x)}{3x}\to1 (Section 5) and sin⁡2x2x→1\dfrac{\sin2x}{2x}\to1 (Section 4), so …

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