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Exercise: Limits of Polynomial and Ra... · Q15

Q.Evaluate lim⁡x→2x5−32x−2\lim_{x\to2}\dfrac{x^5-32}{x-2} using the standard limit formula.

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Since 32=2532=2^5, this matches the standard form with n=5, a=2n=5,\ a=2 (Section 3):

lim⁡x→2x5−25x−2=5(2)5−1=5(2)4=5(16)=80.\lim_{x\to2}\frac{x^5-2^5}{x-2} = 5(2)^{5-1} = 5(2)^4 = 5(16) = 80. …

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