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Exercise: Intuitive Idea of Limit · Q11

Q.By considering values of xx close to 33, on both sides, determine lim⁡x→3x2−9x−3\lim_{x\to3}\dfrac{x^2-9}{x-3}.

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✓ Free question

For xx close to 33 but not equal to it, x2−9x−3=(x−3)(x+3)x−3=x+3\dfrac{x^2-9}{x-3}=\dfrac{(x-3)(x+3)}{x-3}=x+3. As x→3−x\to3^- (e.g. x=2.9,2.99,…x=2.9,2.99,\ldots) and as x→3+x\to3^+ (e.g. x=3.1,3.01,…x=3.1,3.01,\ldots), x+3x+3 approaches 66 from both sides, so the left-hand and right-hand limits agree:

lim⁡x→3x2−9x−3=6.\lim_{x\to3}\frac{x^2-9}{x-3} = 6.

✓Final answer

lim⁡x→3x2−9x−3=6\lim_{x\to3}\dfrac{x^2-9}{x-3} = 6

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