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Example · Example 6

Q.Evaluate lim⁡x→01−cos⁡xx2\lim_{x\to0}\dfrac{1-\cos x}{x^2}.

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Using 1−cos⁡x=2sin⁡2(x/2)1-\cos x = 2\sin^2(x/2),

1−cos⁡xx2=2sin⁡2(x/2)x2=12(sin⁡(x/2)x/2)2.\frac{1-\cos x}{x^2} = \frac{2\sin^2(x/2)}{x^2} = \frac12\left(\frac{\sin(x/2)}{x/2}\right)^2.

As x→0x\to0, also x/2→0x/2\to0, so sin⁡(x/2)/(x/2)→1\sin(x/2)/(x/2)\to1, giving …

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