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Exercise: Limits of Exponential and L... · Q20

Q.Evaluate lim⁡x→0e5x−1x\lim_{x\to0}\dfrac{e^{5x}-1}{x}.

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✓ Free question

Using the scaling technique of Section 5,

e5x−1x=5⋅e5x−15x →x→0 5(1)=5.\frac{e^{5x}-1}{x} = 5\cdot\frac{e^{5x}-1}{5x} \ \xrightarrow[x\to0]{}\ 5(1) = 5.

✓Final answer

lim⁡x→0e5x−1x=5\lim_{x\to0}\dfrac{e^{5x}-1}{x} = 5

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