Write a C program to accept the radius of a circle and compute the area and its perimeter. Radius, r=7m.

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Q. Write a C program to accept the radius of a circle and compute the area and its perimeter. Radius, r=7m.

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Concept understanding — Arithmetic Operators and Expressions in C

Arithmetic operators carry out the basic mathematical operations in C. There are five of them:

+ addition, - subtraction, * multiplication, / division, and
% the modulus (remainder) operator, which gives the remainder of an integer division.

An arithmetic expression is formed by joining variables and constants with these operators, for example y = 3*x*x + 4*x - 2;, which is the C form of $y = 3x^2 + 4x - 2$ . Note that C has no power symbol, so $x^2$ is written as x*x, and multiplication must be written explicitly with *.

Two rules matter when evaluating arithmetic:

Integer division truncates. When both operands are integers, / discards the fractional part, so 25/6 gives 4, not 4.166. To get a real result, at least one operand must be real (e.g. sum/4.0). …

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[!TLDR]

Area = pirr and perimeter = 2pir; for r = 7 m the area is 153.94 sq.m and the perimeter is 43.98 m.

The program reads the radius r and applies the circle formulas with pi defined as a symbolic constant. The area is $\pi r^{2}$ and the perimeter (circumference) is $2\pi r$ .

#include <stdio.h>
#define PI 3.14159
int main()
{
    float r, area, perimeter;
    printf("Enter the radius of the circle: ");
    scanf("%f", &r);
    area = PI * r * r;
    perimeter = 2 * PI * r;
    printf("Area = %.2f sq.m\n", area);
    printf("Perimeter = %.2f m\n", perimeter); …

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Q.Write a C program to accept the radius of a circle and compute the area and its perimeter. Radius, r=7m.

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