Write a C program to convert the given number of days into months and days. Enter days as 196 days.

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Q. Write a C program to convert the given number of days into months and days. Enter days as 196 days.

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Concept understanding — Arithmetic Operators and Expressions in C

Arithmetic operators carry out the basic mathematical operations in C. There are five of them:

+ addition, - subtraction, * multiplication, / division, and
% the modulus (remainder) operator, which gives the remainder of an integer division.

An arithmetic expression is formed by joining variables and constants with these operators, for example y = 3*x*x + 4*x - 2;, which is the C form of $y = 3x^2 + 4x - 2$ . Note that C has no power symbol, so $x^2$ is written as x*x, and multiplication must be written explicitly with *.

Two rules matter when evaluating arithmetic:

Integer division truncates. When both operands are integers, / discards the fractional part, so 25/6 gives 4, not 4.166. To get a real result, at least one operand must be real (e.g. sum/4.0). …

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[!TLDR]

Divide the days by 30: the quotient gives months and the remainder gives the leftover days; 196 days = 6 months and 16 days.

Taking one month as 30 days, the total days are split using integer division and modulus: months = days / 30 and remaining days = days % 30.

#include <stdio.h>
int main()
{
    int days, months, rem;
    printf("Enter the number of days: ");
    scanf("%d", &days);
    months = days / 30;
    rem = days % 30; …

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Q.Write a C program to convert the given number of days into months and days. Enter days as 196 days.

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