Q.Write a C program to illustrate the compact representation of arithmetic operations.

#include<stdio.h>  
void main()  
{  
    int x=2, y=4, z=1;  
    x+=y;  
    y-=x;  
    z*=x;  
    printf("%d\n",x);  
    printf("%d\n",y);  
    printf("%d\n",z);  
}  

The shorthand assignment operators combine an arithmetic operation with assignment, so x+=y means x=x+y, y-=x means y=y-x and z*=x means z=z*x, each using the value the variable holds at …

[!TLDR]

Compound assignment operators (+=, -=, *=) apply the operation to the variable's current value; evaluating them in order gives x=6, y=-2, z=6.

A shorthand (compound) assignment operator such as x += y is equivalent to x = x + y, and similarly y -= x means y = y - x and z *= x means z = z * x. Each uses the value stored at the instant it runs, so the order matters. Tracing with x = 2, y = 4, z = 1:

• x += y; : x = 2 + 4 = 6.
• y -= x; : y = 4 - 6 = -2 (x is now 6).
• z *= x; : z = 1 x 6 = 6.

The three printf statements then display x, y and z on separate lines. A complete standard version is:

#include <stdio.h>

int main(void)
{ …