Q.Write a C program to illustrate the use of an increment operator.

#include<stdio.h>  
void main()  
{  
    int a=6, b=8;  
    printf("a=%d\h",a++);  
    printf("b=%d\h",++b);  
}  

The increment operator ++ adds one to a variable, but its position matters: post-increment (a++) uses the current value first and then increments, while pre-increment (++b) increments first and then uses the new value. …

[!TLDR]

Post-increment (a++) yields the value before adding one, so it prints 6; pre-increment (++b) yields the value after adding one, so it prints 9.

The increment operator ++ increases an integer by one and can be written before the variable (pre-increment, ++a) or after it (post-increment, a++). The two forms differ in the value they return to the surrounding expression:

• In post-increment a++, the current value of a is used first and only then is a increased by one. With a = 6, printf("a=%d", a++) prints 6, after which a becomes 7.
• In pre-increment ++b, b is increased by one first and the new value is used. With b = 8, printf("b=%d", ++b) prints 9.

A complete, corrected version is:

#include <stdio.h>

int main(void)
{
    int a = 6, b = 8;
    printf("a=%d\n", a++);
    printf("b=%d\n", ++b);
    return 0;
}

Output:

a=6
b=9 …