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Answer the following · Q29

Q.Decay constant of 197Hg is 0.017 h-1. What is its half life?

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Step 1. Use t1/2 = 0.693/λ with λ = 0.017 h^-1.

Step 2. t1/2 = 0.693/0.017 ≈ 40.76 h, which rounds to about 40.8 hours. …

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