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Solve · Q44

Q.A sample of old wood shows 7.0 dps/g. If the fresh sample of tree shows 16.0 dps/g, How old is the given sample of wood? Half life of 14C is 5730 y.
(Ans. 6833 g)

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
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Step 1. Activity ratio: A0/A = 16.0 / 7.0 = 2.2857 (fresh sample activity over old sample activity, both per gram, so the per-gram basis cancels).

Step 2. λ for 14C = 0.693/5730 y.

Step 3. t = (1/λ) x ln(A0/A) = (5730/0.6931) x ln(2.2857) = 8267.3 x 0.8267 ≈ 6834 years.

Step 4. FIDELITY NOTE: the book's own printed answer for this problem is '(Ans. 6833 g)'. The numeric value, 6833, matches this independent calculation closely (6834 vs 6833, agreeing to within normal rounding) -- but the unit 'g' (grams) is physically nonsensical for an AGE, and is almost certainly a printing/OCR error for 'y' (years), the unit every other half-life/age answer in …

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