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Solve · Q43

Q.It has been found that the Sun’s mass loss is 4.34 × 10^9 kg per second. How much energy per second would be radiated into space by the Sun?
(Ans.: 3.9 × 10^23 kJ/s)

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Step 1. Mass-energy equivalence: E = mc^2, using the Sun's mass loss rate m = 4.34 x 10^9 kg/s and the speed of light c = 3 x 10^8 m/s (the value used consistently elsewhere in this chapter).

Step 2. E = 4.34 x 10^9 kg/s x (3 x 10^8 m/s)^2 = 4.34 x 10^9 x 9 x 10^16 = 39.06 x 10^25 = 3.906 x 10^26 J/s.

Step 3. Converting joules to kilojoules (divide by 1000): E = 3.906 x 10^23 kJ/s. …

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