Solve · Q43
Q.It has been found that the Sun’s mass loss is 4.34 × 10^9 kg per second. How much energy per second would be radiated into space by the Sun?
(Ans.: 3.9 × 10^23 kJ/s)
Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
98% · 45/46 Questions
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →Step 1. Mass-energy equivalence: E = mc^2, using the Sun's mass loss rate m = 4.34 x 10^9 kg/s and the speed of light c = 3 x 10^8 m/s (the value used consistently elsewhere in this chapter).
Step 2. E = 4.34 x 10^9 kg/s x (3 x 10^8 m/s)^2 = 4.34 x 10^9 x 9 x 10^16 = 39.06 x 10^25 = 3.906 x 10^26 J/s.
Step 3. Converting joules to kilojoules (divide by 1000): E = 3.906 x 10^23 kJ/s. …
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.