Solve · Q32
Q.Half life of 18F is 110 minutes. What fraction of 18F sample decays in 20 minutes?
(Ans. : 0.118)
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✓ Free question
Step 1. λ = 0.693/t1/2 = 0.693/110 min ≈ 0.0063 min^-1.
Step 2. Fraction remaining after 20 min: N/N0 = e^(-λt) = e^(-0.0063 x 20) = e^(-0.126) ≈ 0.8817.
Step 3. Fraction DECAYED = 1 - N/N0 = 1 - 0.8817 ≈ 0.1183.
Step 4. This matches the book's printed answer of 0.118 -- independently verified, no discrepancy.
✓Final answer
About 0.118 (11.8%) of the 18F sample decays in 20 minutes.
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