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Solve · Q33

Q.Half life of 35S is 87.8 d. What percentage of 35S sample remains after 180 d?
(Ans. : 24.2%)

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✓ Free question

Step 1. λ = 0.693/87.8 d ≈ 0.007893 d^-1.

Step 2. N/N0 = e^(-λt) = e^(-0.007893 x 180) = e^(-1.4207) ≈ 0.2416.

Step 3. As a percentage, 0.2416 x 100 ≈ 24.16%, which rounds to 24.2%.

Step 4. This matches the book's printed answer of 24.2% -- independently verified, no discrepancy.

✓Final answer

About 24.2% of the 35S sample remains after 180 days.

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