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Exercise · Q29

Q.Answer the following question.
The electronic configuration of oxygen is written as 1s² 2s² 2px² 2py¹ 2pz¹ and not as 1s² 2s² 2px², 2py² 2pz⁰, Explain.

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Step 1. Oxygen has 8 electrons. Filling by Aufbau: 1s2 2s2 2p41s^2\,2s^2\,2p^4 — four electrons go into the three degenerate 2p orbitals.

Step 2. Apply Hund's rule. The first three of those four 2p electrons must occupy the three separate orbitals singly (2pₓ¹2p_y¹2p_z¹) before any pairing is allowed. Only the FOURTH electron pairs up, entering one already-occupied orbital: 2px2 2py1 2pz12p_x^2\,2p_y^1\,2p_z^1.

Step 3. Why the alternative is wrong. 2px2 2py2 2pz02p_x^2\,2p_y^2\,2p_z^0 pairs electrons in TWO orbitals (pₓ and p_y) while leaving a third (p_z) completely empty — this violates Hund's rule, since p_z should have received an electron before p_y was paired. …

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