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EXERCISE 8.1 · Q30

Q.If f(x)=cos⁡2x−sin⁡2x−13x2+1−1f(x) = \dfrac{\cos^2 x - \sin^2 x - 1}{\sqrt{3x^2+1} - 1} for x≠0x \ne 0, is continuous at x=0x = 0 then find f(0)f(0).

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f(x)=cos⁡2x−sin⁡2x−13x2+1−1f(x)=\dfrac{\cos^2x-\sin^2x-1}{\sqrt{3x^2+1}-1} for x≠0x\ne0, continuous at 00.

Numerator: cos⁡2x−sin⁡2x=cos⁡2x\cos^2x-\sin^2x=\cos2x, so numerator =cos⁡2x−1=−2sin⁡2x=\cos2x-1=-2\sin^2x.

Denominator: rationalise by multiplying by the conjugate: (3x2+1−1)(3x2+1+1)=3x2+1−1=3x2\big(\sqrt{3x^2+1}-1\big)\big(\sqrt{3x^2+1}+1\big)=3x^2+1-1=3x^2, so 3x2+1−1=3x23x2+1+1\sqrt{3x^2+1}-1=\dfrac{3x^2}{\sqrt{3x^2+1}+1}. …

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