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EXERCISE 8.1 · Q34

Q.If f(x)=sin⁡2x5x−af(x) = \dfrac{\sin 2x}{5x} - a, for x>0x > 0, =4= 4 for x=0x = 0, =x2+b−3= x^2+b-3, for x<0x < 0, is continuous at x=0x = 0, find aa and bb.

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f(x)=sin⁡2x5x−af(x)=\dfrac{\sin2x}{5x}-a for x>0x>0, f(0)=4f(0)=4, and f(x)=x2+b−3f(x)=x^2+b-3 for x<0x<0; continuous at 00.

Right-hand limit: lim⁡x→0+(sin⁡2x5x−a)=lim⁡x→025⋅sin⁡2x2x−a=25(1)−a=25−a\displaystyle\lim_{x\to0^+}\left(\frac{\sin2x}{5x}-a\right)=\lim_{x\to0}\frac25\cdot\frac{\sin2x}{2x}-a=\frac25(1)-a=\frac25-a.

Hold on — matching to f(0)=4f(0)=4: 25−a=4⇒a=25−4=−185\dfrac25-a=4\Rightarrow a=\dfrac25-4=-\dfrac{18}{5}. …

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