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EXERCISE 8.1 · Q27

Q.Which of the following functions has a removable discontinuity? If it has a removable discontinuity, redefine the function so that it becomes continuous: f(x)=3x+2f(x) = 3x+2, for −4≤x≤−2-4 \le x \le -2, =2x−3= 2x-3, for −2<x≤6-2 < x \le 6.

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f(x)=3x+2f(x)=3x+2 for −4≤x≤−2-4\le x\le-2, and f(x)=2x−3f(x)=2x-3 for −2<x≤6-2<x\le6. Here f(−2)=3(−2)+2=−4f(-2)=3(-2)+2=-4 (from the first piece, which includes x=−2x=-2).

Left-hand limit: lim⁡x→−2−f(x)=3(−2)+2=−4\displaystyle\lim_{x\to-2^-} f(x)=3(-2)+2=-4 (matches f(−2)f(-2), since the first piece is continuous on its own).

Right-hand limit: lim⁡x→−2+f(x)=2(−2)−3=−4−3=−7\displaystyle\lim_{x\to-2^+} f(x)=2(-2)-3=-4-3=-7. …

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