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EXERCISE 8.1 · Q1

Q.Examine the continuity of f(x)=x3+2x2−x−2f(x) = x^3 + 2x^2 - x - 2 at x=−2x = -2.

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✓ Free question

f(x)=x3+2x2−x−2f(x)=x^3+2x^2-x-2 is a polynomial, and every polynomial is continuous at every point of R\mathbb{R} (it is built from the continuous power functions x3,x2,xx^3,x^2,x and constants using only sums and constant multiples, all of which preserve continuity). So it suffices to check the three conditions directly at x=−2x=-2.

f(−2)=(−2)3+2(−2)2−(−2)−2=−8+8+2−2=0.f(-2)=(-2)^3+2(-2)^2-(-2)-2=-8+8+2-2=0.

Because ff is a polynomial, lim⁡x→−2f(x)=f(−2)=0\displaystyle\lim_{x\to-2} f(x)=f(-2)=0 automatically (limits of polynomials are found by direct substitution).

Since f(−2)f(-2) is defined, the limit exists, and lim⁡x→−2f(x)=f(−2)=0\displaystyle\lim_{x\to-2} f(x)=f(-2)=0, all three conditions of continuity hold.

✓Final answer

f(x)=x3+2x2−x−2f(x)=x^3+2x^2-x-2 is continuous at x=−2x=-2, with f(−2)=0f(-2)=0.

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