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EXERCISE 8.1 · Q32

Q.If f(x)=24x−8x−3x+112x−4x−3x+1f(x) = \dfrac{24^x-8^x-3^x+1}{12^x-4^x-3^x+1}, for x≠0x \ne 0, =k= k, for x=0x = 0, is continuous at x=0x = 0, find kk.

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f(x)=24x−8x−3x+112x−4x−3x+1f(x)=\dfrac{24^x-8^x-3^x+1}{12^x-4^x-3^x+1} for x≠0x\ne0, f(0)=kf(0)=k, continuous at 00.

Numerator: since 24x=8x⋅3x24^x=8^x\cdot3^x, 24x−8x−3x+1=8x(3x−1)−(3x−1)=(3x−1)(8x−1)24^x-8^x-3^x+1=8^x(3^x-1)-(3^x-1)=(3^x-1)(8^x-1).

Denominator: since 12x=4x⋅3x12^x=4^x\cdot3^x, 12x−4x−3x+1=4x(3x−1)−(3x−1)=(3x−1)(4x−1)12^x-4^x-3^x+1=4^x(3^x-1)-(3^x-1)=(3^x-1)(4^x-1). …

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