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EXERCISE 8.1 · Q19

Q.Show that the following function has continuous extension to the point where f(x)f(x) is not defined. Also find the extension: f(x)=3sin⁡2x+2cos⁡x(1−cos⁡2x)2(1−cos⁡2x)f(x) = \dfrac{3\sin^2 x + 2\cos x(1-\cos 2x)}{2(1-\cos^2 x)}, for x≠0x \ne 0.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
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f(x)=3sin⁡2x+2cos⁡x(1−cos⁡2x)2(1−cos⁡2x)f(x)=\dfrac{3\sin^2x+2\cos x(1-\cos2x)}{2(1-\cos^2x)} for x≠0x\ne0; f(0)f(0) undefined since 1−cos⁡20=01-\cos^20=0.

Denominator: 2(1−cos⁡2x)=2sin⁡2x2(1-\cos^2x)=2\sin^2x.

Numerator: using 1−cos⁡2x=2sin⁡2x1-\cos2x=2\sin^2x, 3sin⁡2x+2cos⁡x(2sin⁡2x)=3sin⁡2x+4sin⁡2xcos⁡x=sin⁡2x(3+4cos⁡x)3\sin^2x+2\cos x(2\sin^2x)=3\sin^2x+4\sin^2x\cos x=\sin^2x(3+4\cos x). …

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