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EXERCISE 8.1 · Q42

Q.Activity: Let f(x)=ax+bf(x) = ax + b (where aa and bb are unknown), for x<1x < 1, =x2+5= x^2 + 5, for x≥1x \ge 1. Find the values of aa and bb, so that f(x)f(x) is continuous at x=1x = 1. (Fig. 8.11)

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Here f(x)=ax+bf(x)=ax+b for x<1x<1, and f(x)=x2+5f(x)=x^2+5 for x≥1x\ge1 (Fig. 8.11 shows the parabola-branch value at x=1x=1 as a solid dot at height 66). Since x=1x=1 belongs to the second piece, f(1)=12+5=6f(1)=1^2+5=6.

For continuity at x=1x=1, the left-hand limit (from the line) must equal f(1)f(1):

lim⁡x→1−(ax+b)=a+b.\lim_{x\to1^-}(ax+b)=a+b.

Setting this equal to f(1)=6f(1)=6:

a+b=6.a+b=6. …

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