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Miscellaneous Exercise 4(B) · Q178

Q.If [x3x−yzx+z3y−w]=[3247]\begin{bmatrix}x & 3x-y\\zx+z & 3y-w\end{bmatrix}=\begin{bmatrix}3 & 2\\4 & 7\end{bmatrix} then .......... (A) x=3,y=7,z=1,w=14x=3,y=7,z=1,w=14 (B) x=3,y=−5,z=−1,w=−4x=3,y=-5,z=-1,w=-4 (C) x=3,y=6,z=2,w=7x=3,y=6,z=2,w=7 (D) x=−3,y=−7,z=−1,w=−14x=-3,y=-7,z=-1,w=-14

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[x3x−yzx+z3y−w]=[3247]\begin{bmatrix}x & 3x-y\\zx+z & 3y-w\end{bmatrix}=\begin{bmatrix}3 & 2\\4 & 7\end{bmatrix}.

Entry(1,1): x=3x=3.

Entry(1,2): 3x−y=2⇒9−y=2⇒y=73x-y=2\Rightarrow 9-y=2\Rightarrow y=7. …

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