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Miscellaneous Exercise 4(B) · Q183

Q.If f(α)=A=[cos⁡α−sin⁡α0sin⁡αcos⁡α0001]f(\alpha)=A=\begin{bmatrix}\cos\alpha & -\sin\alpha & 0\\\sin\alpha & \cos\alpha & 0\\0 & 0 & 1\end{bmatrix}, Find f(−α)f(-\alpha)

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f(α)=A=[cos⁡α−sin⁡α0sin⁡αcos⁡α0001]f(\alpha)=A=\begin{bmatrix}\cos\alpha & -\sin\alpha & 0\\\sin\alpha & \cos\alpha & 0\\0 & 0 & 1\end{bmatrix}.

Substitute α→−α\alpha\to-\alpha: cos⁡(−α)=cos⁡α\cos(-\alpha)=\cos\alpha and sin⁡(−α)=−sin⁡α\sin(-\alpha)=-\sin\alpha. …

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