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Miscellaneous Exercise 4(B) · Q172

Q.Consider the matrices A=[46−13021−25]A=\begin{bmatrix}4 & 6 & -1\\3 & 0 & 2\\1 & -2 & 5\end{bmatrix}, B=[2401−12]B=\begin{bmatrix}2 & 4\\0 & 1\\-1 & 2\end{bmatrix}, C=[312]C=\begin{bmatrix}3\\1\\2\end{bmatrix} out of the given matrix product ............ i) (AB)TC(AB)^TC ii) CTC(AB)TC^TC(AB)^T iii) CTABC^TAB iv) ATABBTCA^TABB^TC (A) Exactly one is defined (B) Exactly two are defined (C) Exactly three are defined (D) all four are defined

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AA is 3×33\times3, BB is 3×23\times2, CC is 3×13\times1. So ABAB is 3×23\times2, (AB)T(AB)^T is 2×32\times3, ATA^T is 3×33\times3, BTB^T is 2×32\times3, CTC^T is 1×31\times3.

i) (AB)TC(AB)^TC: (2×3)(3×1)(2\times3)(3\times1) — cols(2nd factor's rows)=3 matches — defined, gives 2×12\times1.

ii) CTC(AB)TC^TC(AB)^T: CTCC^TC is (1×3)(3×1)=1×1(1\times3)(3\times1)=1\times1. To multiply this 1×11\times1 by (AB)T(AB)^T which is 2×32\times3, we need columns of first (1) to equal rows of second (2) — NOT equal, so as a matrix product this is undefined.

iii) CTABC^TAB: (1×3)(3×3)(3×2)=1×2(1\times3)(3\times3)(3\times2)=1\times2 — every step conformable — defined.

iv) ATABBTCA^TABB^TC: (3×3)(3×3)(3×2)(2×3)(3×1)(3\times3)(3\times3)(3\times2)(2\times3)(3\times1) — every step conformable — defined, gives 3×13\times1.

So exactly three products (i, iii, iv) are defined.

✓Final answer

Option (C) Exactly three are defined

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