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Miscellaneous Exercise 4(B) · Q202

Q.If A=[2−13−2]A=\begin{bmatrix}2 & -1\\3 & -2\end{bmatrix}, find A3A^3.

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A=[2−13−2]A=\begin{bmatrix}2 & -1\\3 & -2\end{bmatrix}.

A2=[2(2)+(−1)(3)2(−1)+(−1)(−2)3(2)+(−2)(3)3(−1)+(−2)(−2)]=[4−3−2+26−6−3+4]=[1001]=IA^2=\begin{bmatrix}2(2)+(-1)(3) & 2(-1)+(-1)(-2)\\3(2)+(-2)(3) & 3(-1)+(-2)(-2)\end{bmatrix}=\begin{bmatrix}4-3 & -2+2\\6-6 & -3+4\end{bmatrix}=\begin{bmatrix}1 & 0\\0 & 1\end{bmatrix}=I. …

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